6q^2+11qd-35d^2=

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Solution for 6q^2+11qd-35d^2= equation:


Simplifying
6q2 + 11qd + -35d2 = 0

Reorder the terms:
11dq + -35d2 + 6q2 = 0

Solving
11dq + -35d2 + 6q2 = 0

Solving for variable 'd'.

Factor a trinomial.
(-7d + -2q)(5d + -3q) = 0

Subproblem 1

Set the factor '(-7d + -2q)' equal to zero and attempt to solve: Simplifying -7d + -2q = 0 Solving -7d + -2q = 0 Move all terms containing d to the left, all other terms to the right. Add '2q' to each side of the equation. -7d + -2q + 2q = 0 + 2q Combine like terms: -2q + 2q = 0 -7d + 0 = 0 + 2q -7d = 0 + 2q Remove the zero: -7d = 2q Divide each side by '-7'. d = -0.2857142857q Simplifying d = -0.2857142857q

Subproblem 2

Set the factor '(5d + -3q)' equal to zero and attempt to solve: Simplifying 5d + -3q = 0 Solving 5d + -3q = 0 Move all terms containing d to the left, all other terms to the right. Add '3q' to each side of the equation. 5d + -3q + 3q = 0 + 3q Combine like terms: -3q + 3q = 0 5d + 0 = 0 + 3q 5d = 0 + 3q Remove the zero: 5d = 3q Divide each side by '5'. d = 0.6q Simplifying d = 0.6q

Solution

d = {-0.2857142857q, 0.6q}

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